Class 4

Punjab State Board PSEB 4th Class Maths Book Solutions Chapter 5 Measurement Ex 5.5 Textbook Exercise Questions and Answers.

PSEB Solutions for Class 4 Maths Chapter 5 Measurement Ex 5.5

Question 1.
Add the following :
(a) 8 m 40 cm + 4 m 35 cm
Solution:

(b) 2 m 62 cm + 6 m 25 cm
Solution:

(c) 5 m 37 cm + 7 m 20 cm
Solution:

(d) 3 m 45 cm + 6 m 15 cm
Solution:

(e) 1 m 50 cm + 2 m 25 cm
Solution:

(f) 9 m 44 cm + 5 m 35 cm
Solution:

Question 2.
Subtract :
(a) 9 m 70 cm – 7 m 35 cm
Solution:

(b) 6 m 84 cm – 1 m 35 cm
Solution:

(c) 5 m 72 cm – 3 m 60 cm
Solution:

(d) 4 m 18 cm – 3 m 12 cm
Solution:

(e) 9 m 50 cm – 4 m 25 cm
Solution:

(f) 5 m 81 cm – 5 m 75 cm
Solution:

Question 3.
Maya uses lm 50cm red ribbon and 2m25cm green ribbon to make a flower. How much total ribbon did she use ?
Solution:
Length of red ribbon used = 1 m 50 cm
Length of green ribbon used = 2 m 25 cm
Total Length of used = 3 m 75 cm

Question 4.
Saroj bought 5m50cm cloth for herself and 3m25cm for her daughter. Find the total length of cloth did she buy ?
Solution:
Saroj bought cloth for herself = 5 m 50 cm
Saroj bought cloth for her daughter = + 3 m 25 cm
Total length of cloth she bought = 8 m 75 cm

Punjab State Board PSEB 4th Class Maths Book Solutions Chapter 4 Money (Currency) Ex 4.5 Textbook Exercise Questions and Answers.

PSEB Solutions for Class 4 Maths Chapter 4 Money (Currency) Ex 4.5

1. Divide the following amounts :

Question 1.
₹ 160 ÷ 4
Solution:

∴ ₹ 160 ÷ 4 = ₹ 40

Question 2.
₹ 475 ÷ 5
Solution:

∴ ₹ 475 ÷ 5 = ₹ 95

Question 3.
₹ 564 ÷ 12
Solution:

∴ ₹ 564 ÷ 12 = ₹ 47

Question 4.
₹ 1248 ÷ 6
Solution:

∴ ₹ 1248 ÷ 6 = ₹ 208

Question 5.
₹ 2665 ÷ 13
Solution:

∴ ₹ 2665 ÷ 13 = ₹ 205

Question 2.
The cost of 18 toy cars is ₹ 450. Find the cost of one toy car ?
Solution:
Cost of 18 toy cars = ₹ 450
Cost of 1 toy car = ₹ 450 ÷ 18
= ₹ 25

Question 3.
The cost of 13 books is ₹ 936. Find the cost of one book.
Solution:
Cost of 13 books = ₹ 936
Cost of 1 book = ₹ 936 ÷ 13
= ₹ 72.

Question 4.
The cost of a dozen oranges is ₹ 84. Find the cost of one orange.
Solution:
Cost of one dozen i.e. 12 oranges = ₹ 84
Cost of one orange = ₹ 84 ÷ 12
= ₹ 7

Question 5.
An amount of ₹ 2848 is to be distributed among 16 children. What amount will each child get ?
Solution:
Amount to be distributed among 16 children = ₹ 2848
Amount received by each child = ₹ 2848 ÷ 16
= ₹ 178

Question 6.
A school received ₹ 9120 to buy uniforms for 19 children of class 4. How much amount did the school get for each uniform.
Solution:
Total amount received by the school = ₹ 9120
No. of children = 19
Amount of money school received for each uniform
= ₹ 9120 ÷ ₹ 19
= ₹ 480.

Punjab State Board PSEB 4th Class Maths Book Solutions Chapter 5 Measurement Ex 5.4 Textbook Exercise Questions and Answers.

PSEB Solutions for Class 4 Maths Chapter 5 Measurement Ex 5.4

Question 1.
Draw a line segment by joining the given points and measure their lengths:

Solution:
(a)

(b)

(c)

Question 2.
Draw line segment of given lengths:
(a) 5 cm
Solution:

(b) 8 cm
Solution:

(c) 6 cm
Solution:

(d) 2 cm
Solution:

(e) 7 cm
Solution:

(f) 9 cm
Solution:

Punjab State Board PSEB 4th Class Maths Book Solutions Chapter 4 Money (Currency) Ex 4.4 Textbook Exercise Questions and Answers.

PSEB Solutions for Class 4 Maths Chapter 4 Money (Currency) Ex 4.4

1. Find the product:

Question 1.
₹ 25 × 6
Solution:

Question 2.
₹ 30 × 7
Solution:

Question 3.
₹49 × 8
Solution:

Question 4.
₹ 175 × 8
Solution:

Question 5.
₹ 400 × 5
Solution:

Question 6.
₹ 312 × 3
Solution:

Question 7.
₹ 27 × 15
Solution:

Question 8.
₹ 48 × 76
Solution:

Question 9.
₹ 82 × 67
Solution:

Question 2.
The cost of a doll is ₹ 70. Find the cost of 5 such dolls.
Solution:
Cost of.4oll = ₹ 70
Cost of 5 dolls = ₹ 70 × 5
= ₹ 350

Question 3.
Manveet bought a jacket of ₹ 460. Find the cost of 9 such jackets.
Solution:
Cost of jacket = ₹ 460
Cost of 9 jackets = ₹ 460 × 9 = ₹ 4,140

Question 4.
Sukhdev bought 35 balloons ₹ 15 per balloon. How much did he pay to the balloon seller ?
Solution:
Cost of 1 balloon = ₹ 15
Cost of 35 balloons = ₹ 15 × 35 = ₹ 525

Question 5.
The cost of a banana is ₹ 8. What is the cost a dozen bananas ?
Solution:
Cost of 1 banana = ₹ 8
Cost of 1 dozen i.e. 12 bananas = ₹ 8 × 12
= ₹ 96.

Punjab State Board PSEB 4th Class Maths Book Solutions Chapter 4 Money (Currency) Ex 4.3 Textbook Exercise Questions and Answers.

PSEB Solutions for Class 4 Maths Chapter 4 Money (Currency) Ex 4.3

1. Manveet bought following things in a fair. How much money will she pay to the shopkeeper?

Question 1.

Solution:

Question 2.

Solution:

Question 3.

Solution:

Question 4.

Solution:

2. Supreet bought the following things and gave money. How much amount will the shopkeeper return to Supreet?

Question 1.

Solution:

Question 2.

Solution:

Question 3.
Avneet bought a chocolate worth of ₹ 72 and a juice worth ₹ 35. What amount will Avneet pay to shopkeeper?
Solution:
Cost price of a chocolate = ₹ 72
Cost price of juice = ₹ 35
Total cost of both = ₹ 107

Avneet will pay ₹ 107 to shopkeeper.

Question 4.
Supreet bought a school bag worth ₹ 365. He gave ₹ 500 to shopkeeper. How much money will be returned by the shopkeeper?
Solution:
Amount given to shopkeeper = ₹ 500
Cost price of a school bag = ₹ 365

Shopkeeper will return ₹ 135 to him.

Question 5.
Vinod bought a book worth ₹ 247.75, copies worth ₹ 180.60 and a pen worth ₹ 35.20. How much did he spend in all?
Solution:
Cost price of a book = ₹ 247.75
Cost price of note books = ₹ 180.60
Cost price of a pen = ₹ 35.20
Total cost of all the items = ₹ 463.55

He spent ₹ 463.55.

Question 6.
Tanisha wants to buy a battery car worth ₹ 945 for her $other. She has ₹ 820. How much money does she require more to buy it?
Solution:
Cost price of the battery car = ₹ 945
She has money with her = ₹ 820
More money requirement to buy it = ₹ 125

Punjab State Board PSEB 4th Class Maths Book Solutions Chapter 5 Measurement Ex 5.3 Textbook Exercise Questions and Answers.

PSEB Solutions for Class 4 Maths Chapter 5 Measurement Ex 5.3

(1 metre = 100 cm)

Question 1.
Convert into metre:
(a) 400 cm = ……. m
Solution:
4 m

(b) 700 cm = ……. m
Solution:
7 m

(c) 200 cm = …….. m
Solution:
2 m

(d) 800 cm = ……. m
Solution:
8 m

(e) 500 cm = ……….. m
Solution:
5 m

(f) 900 cm = …….. m
Solution:
9 in.

Question 2.
Convert into centimetres :
(a) 3 m = …… cm
Solution:
3 m = 3 × 100 cm
= 300 cm

(b) 6 m = …… cm
Solution:
6 m = 6 × 100 cm
= 600 cm

(c) 4 m = …… cm
Solution:
4 m = 4 × 100 cm
= 400 cm

(d) 9 m = ……. cm
Solution:
9 m = 9 × 100 cm
= 900 cm

(e) 2 m = …….. cm
Solution:
2 m = 2 × 100 cm
= 200 cm

(f) 5m = ……. cm
Solution:
5 m = 5 × 100 cm
= 500 cm

Question 3.
Mohit measures length of given items with help of a 30 cm scale. Show this length in metre and centimetres.

Solution:

1. 1 m 8 cm.
2. 1 m 32 cm.
3. 3 m 5 cm.
4. 4 m 50 cm.

Question 4.
Estimate the distance in metres and also find the actual distance with the help of metre rod or measurement tape.

Solution:
Try yourself.

Punjab State Board PSEB 4th Class Maths Book Solutions Chapter 4 Money (Currency) Ex 4.2 Textbook Exercise Questions and Answers.

PSEB Solutions for Class 4 Maths Chapter 4 Money (Currency) Ex 4.2

1. Add the amount of the following currency notes:

Question 1.

Solution:
₹ 170

Question 2.

Solution:
₹ 310

Question 3.

Solution:
₹ 525

Question 4.

Solution:
₹ 230

Question 5.

Solution:
₹ 157

2. Find the sum of following amounts :

Question 1.
₹ 200, ₹ 50, ₹ 20
Solution:
₹ 200, ₹ 50, ₹ 20

Question 2.
₹ 350, ₹ 165, ₹ 75
Solution:
₹ 350, ₹ 165, ₹ 75

Question 3.
₹ 470, ₹ 105, ₹ 55
Solution:
₹ 470, ₹ 105, ₹ 55

Question 4.
₹ 250, ₹ 90, ₹ 110
Solution:
₹ 250, ₹ 90, ₹ 110

Question 5.
₹ 200, ₹ 160, ₹ 50
Solution:
₹ 200, ₹ 160, ₹ 50

3. Find the difference (subtract) of following amounts :

Question 1.
₹ 200 and ₹ 150
Solution:
₹ 200. ₹ 150

Question 2.
₹ 450 and ₹ 200
Solution:
₹ 450, ₹ 200

Question 3.
₹ 500 and ₹ 270
Solution:
₹ 500, ₹ 270

Question 4.
₹ 120 and ₹ 75
Solution:
₹ 120, ₹ 75

Question 5.
₹ 300 and ₹ 125
Solution:
₹ 300, ₹ 125

4. Put (✓) on the currency note or coins which are required for buying given things :

Question 1.

Solution:

Question 2.

Solution:

Question 3.

Solution:

Question 4.

Solution:

Question 5.

Solution:

5. Draw required currency notes and coins for buying things as tender.

Question 1.

Solution:

Question 2.

Solution:

Question 3.

Solution:

Question 4.

Solution:

Question 5.

Solution:

Punjab State Board PSEB 4th Class Maths Book Solutions Chapter 4 Money (Currency) Ex 4.1 Textbook Exercise Questions and Answers.

PSEB Solutions for Class 4 Maths Chapter 4 Money (Currency) Ex 4.1

1. Draw 50 paise coins for given notes/coins :

Question 1.

Solution:

= Take four coins of 50 paise

Question 2.

Solution:

= Take ten coins of 50 paise

Question 3.

Solution:

= Take twenty coins of 50 paise

Question 4.

Solution:

= Take fourteen coins of 50 paise

Question 5.

Solution:

= Take eight coins of 50 paise.

2. Draw notes/coins, converting 50 paise into rupees.

Question 1.

Question 2.

Solution:

Question 3.

Solution:

Punjab State Board PSEB 4th Class Maths Book Solutions Chapter 3 Fractional Numbers Ex 3.1 Textbook Exercise Questions and Answers.

PSEB Solutions for Class 4 Maths Chapter 3 Fractional Numbers Ex 3.1

Question 1.
Match the fraction according to coloured portion:

Solution:
(a) \(\frac{1}{4}\)
(b) \(\frac{3}{4}\)
(c) \(\frac{1}{2}\)
(d) \(\frac{1}{3}\)

Question 2.
Write the fraction of coloured as well as blank portion in the given space :


Solution:

3. Colour the figure according to the given fraction :

Question 1.

Solution:

Question 2.

Solution:

Question 3.

Solution:

Question 4.

Solution:

Question 5.

Solution:

Question 6.

Solution:

4. Mark (✓) on the correct fraction of the coloured portion of the figure:

Question 1.

Solution:
(b) \(\frac{3}{4}\)

Question 2.

Solution:
(d) \(\frac{3}{8}\)

Question 3.

Solution:
(c) \(\frac{1}{4}\)

5. Write the given fraction in words:

Question 1.
\(\frac{1}{2}\)
Solution:
Half

Question 2.
\(\frac{1}{4}\)
Solution:
One Fourth

Question 3.
\(\frac{1}{3}\)
Solution:
One third

Question 4.
\(\frac{2}{3}\)
Solution:
Two third

Question 5.
\(\frac{3}{4}\)
Solution:
Three fourth

Question 6.
\(\frac{1}{10}\)
Solution:
One tenth.

6. Write numerator and denominator of the given fractions :

Question 1.
\(\frac{2}{3}\)
Solution:
Numerator = 2 and Denominator = 3

Question 2.
\(\frac{1}{2}\)
Solution:
Numerator = 1 and Denominator = 2

Question 3.
\(\frac{1}{4}\)
Solution:
Numerator = 1 and Denominator = 4

Question 4.
\(\frac{3}{4}\)
Solution:
Numerator = 3 and Denominator = 4.

Punjab State Board PSEB 4th Class Maths Book Solutions Chapter 3 ਭਿੰਨਾਤਮਕ ਸੰਖਿਆਵਾਂ Ex 3.1 Textbook Exercise Questions and Answers.

PSEB Solutions for Class 4 Maths Chapter 3 ਭਿੰਨਾਤਮਕ ਸੰਖਿਆਵਾਂ Ex 3.1

ਪ੍ਰਸ਼ਨ 1.
ਚਿੱਤਰ ਦੇ ਰੰਗਦਾਰ ਭਾਗ ਅਨੁਸਾਰ ਸਹੀ ਭਿੰਨ ਨਾਲ ਮਿਲਾਨ ਕਰੋ ।

ਹੱਲ:
(a) \(\frac{1}{4}\),
(b) \(\frac{3}{4}\),
(c) \(\frac{1}{2}\),
(d) \(\frac{1}{3}\)

ਪ੍ਰਸ਼ਨ 2.
ਹੇਠਾਂ ਦਿੱਤੇ ਚਿੱਤਰਾਂ ਦੇ ਰੰਗਦਾਰ ਅਤੇ ਬਿਨਾਂ ਰੰਗਦਾਰ ਹਿੱਸੇ ਦੀ ਭਿੰਨ ਦੱਸੇ ਗਏ ਖਾਨੇ ਵਿੱਚ ਲਿਖੋ :


ਹੱਲ:

ਪ੍ਰਸ਼ਨ 3.
ਹੇਠਾਂ ਦਿੱਤੀ ਭਿੰਨ ਅਨੁਸਾਰ ਚਿੱਤਰ ਵਿੱਚ ਰੰਗ ਭਿੰਨ :

ਹੱਲ:

ਪ੍ਰਸ਼ਨ 4.
ਚਿੱਤਰ ਅਨੁਸਾਰ ਰੰਗਦਾਰ ਹਿੱਸੇ ਦੀ ਬਣਦੀ ਭਿੰਨ ਤੇ ਸਹੀ (✓) ਦਾ ਚਿੰਨ੍ਹ ਲਗਾਓ :

(i)

(a) \(\frac{1}{4}\)
(b) \(\frac{3}{4}\)
(c) \(\frac{4}{4}\)
(d) \(\frac{1}{2}\)
ਹੱਲ:
(b) \(\frac{3}{4}\)

(ii)

(a) \(\frac{5}{8}\)
(b) \(\frac{1}{8}\)
(c) \(\frac{3}{4}\)
(d) \(\frac{3}{8}\)
ਹੱਲ:
(d) \(\frac{3}{8}\)

(iii)

(a) \(\frac{3}{4}\)
(b) \(\frac{2}{4}\)
(c) \(\frac{1}{4}\)
(d) \(\frac{4}{4}\)
ਹੱਲ:
(d) \(\frac{1}{4}\)

ਪ੍ਰਸ਼ਨ 5.
ਹੇਠਾਂ ਦਿੱਤੀਆਂ ਭਿੰਨਾਤਮਕ ਸੰਖਿਆਵਾਂ ਨੂੰ ਸ਼ਬਦਾਂ ਵਿੱਚ ਲਿਖੋ :
(a) \(\frac{1}{2}\)
(b) \(\frac{1}{4}\)
(c) \(\frac{1}{3}\)
(d) \(\frac{2}{3}\)
(e) \(\frac{3}{4}\)
(f) \(\frac{1}{10}\)
ਹੱਲ:
(a) ਅੱਧਾ,
(b) ਇਕ ਚੌਥਾਈ,
(c) ਇਕ ਤਿਹਾਈ,
(d) ਦੋ ਤਿਹਾਈ,
(e) ਤਿੰਨ ਚੌਥਾਈ,
(f) ਇਕ ਦਸਵਾਂ ।

ਪ੍ਰਸ਼ਨ 6.
ਹੇਠਾਂ ਦਿੱਤੀਆਂ ਭਿੰਨਾਂ ਦੇ ਅੰਸ਼ ਅਤੇ ਹਰ ਲਿਖੋ :
(a) \(\frac{2}{3}\)
(b) \(\frac{1}{2}\)
(c) \(\frac{1}{4}\)
(d) \(\frac{3}{4}\)
ਹੱਲ:
(a) ਅੰਸ਼ = 2, ਹਰ = 3,
(b) ਅੰਸ਼ = 1, ਹਰ = 2,
(c) ਅੰਸ਼ = 1, ਹਰ = 4,
(d) ਅੰਸ਼ = 3, ਹਰ = 4.