Punjab State Board PSEB 8th Class Maths Book Solutions Chapter 6 ਵਰਗ ਅਤੇ ਵਰਗਮੂਲ Ex 6.2 Textbook Exercise Questions and Answers.
PSEB Solutions for Class 8 Maths Chapter 6 ਵਰਗ ਅਤੇ ਵਰਗਮੂਲ Exercise 6.2
1. ਹੇਠਾਂ ਲਿਖੀਆਂ ਸਿਖਿਆਵਾਂ ਦਾ ਵਰਗ ਪਤਾ ਕਰੋ :
ਪ੍ਰਸ਼ਨ (i).
32
ਹੱਲ:
(32)2
32 = 30 + 2
(32)2 = (30 + 2)2 = (30 + 2) (30 + 2)
= 30 (30 + 2) + 2 (30 + 2)
= 302 + 30 × 2 + 2 × 30 + 22
= 900 + 60 + 60 + 4
= 1024
ਪ੍ਰਸ਼ਨ (ii).
35
ਹੱਲ:
(35)2
35 = 30 + 5
(35)2 = (30 + 5)2
= (30 + 5) (30 + 5)
= 30 (30 + 5) + 5 (30 + 5)
= 302 + 30 × 5 + 5 × 30 + 52
= 900 + 150 + 150 + 25
= 1225
ਪ੍ਰਸ਼ਨ (iii).
86
ਹੱਲ:
(86)2
86 = 80 + 6
(86)2 = (80 + 6 )2
= (80 + 6) (80 + 6)
= 80 (80 + 6) + 6 (80 + 6)
= 8o2 + 80 × 6 + 6 × 80 + 62
= 6400 + 480 + 480 + 36
= 7396
ਪ੍ਰਸ਼ਨ (iv).
93
ਹੱਲ:
(93)2
93 = 90 + 3
(93)2 = (90 + 3 )2
= (90 + 3) (90 + 3)
= 90 (90 + 3) + 3 (90 + 3)
= 902 + 90 × 3 + 3 × 90 + 32
= 8100 + 270 + 270 + 9
= 8649
ਪ੍ਰਸ਼ਨ (v).
71
ਹੱਲ:
(71)2
71 = 70 + 1
(71)2 = (70 + 1)2
= (70 + 1) (70 + 1)
= 70 (70 + 1) + 1 (70 + 1)
= 702 + 70 × 1 + 1 × 70 + 12
= 4900 + 70 + 70 + 1
= 5041
ਪ੍ਰਸ਼ਨ (vi).
46.
ਹੱਲ:
(46)2
46 = 40 + 6
(46)2 = (40 + 6)2
= (40 + 6) (40 + 6)
= 40 (40 + 6) + 6 (40 + 6)
= 402 + 40 × 6 + 6 × 40 + 62
= 1600 + 240 +240 + 36
= 2116
2. ਪਾਈਥਾਗੋਰੀਅਨ ਕ੍ਰਿਗੁੱਟ ਲਿਖੋ ਜਿਸਦਾ ਇਕ ਮੈਂਬਰ ਹੈ,
ਪ੍ਰਸ਼ਨ (i).
6
ਹੱਲ:
ਮੰਨ ਲਉ 2m = 6
∴ m = \(\frac{6}{2}\) = 3
m2 – 1 = (3)2 – 1 = 9 – 1 = 8
ਅਤੇ m2 + 1 = (3)2 + 1 = 9 + 1 = 10.
ਪ੍ਰਸ਼ਨ (ii).
14
ਹੱਲ:
ਮੰਨ ਲਉ 2m = 14
∴ m = \(\frac{14}{2}\) = 7
∴ m2 – 1 = (7)2 – 1
= 49 – 1 = 48
ਅਤੇ m2 + 1 = (7)2 + 1 = 49 + 1 = 50
ਪ੍ਰਸ਼ਨ (iii).
16
ਹੱਲ:
ਮੰਨ ਲਉ 2m = 16.
∴ m = \(\frac{16}{2}\) = 8
∴ m2 – 1 = (8)2 – 1 = 64 – 1 = 63
ਅਤੇ m2 + 1 = (8)2 + 1 = 64 + 1 = 65
ਪ੍ਰਸ਼ਨ (iv).
18.
ਹੱਲ:
ਮੰਨ ਲਉ 2m = 18
∴ m = \(\frac{18}{2}\) = 9
∴ m2 – 1 = (9)2 – 1 = 81 – 1 = 80
ਅਤੇ m2 + 1 = (9)2 + 1 = 81 +1 = 82