Punjab State Board PSEB 4th Class Maths Book Solutions Chapter 2 Fundamental Operations on Numbers Ex 2.4 Textbook Exercise Questions and Answers.

## PSEB Solutions for Class 4 Maths Chapter 2 Fundamental Operations on Numbers Ex 2.4

1. Find the product of the following :

Question 1.

41 × 4

Solution:

Question 2.

25 × 36

Solution:

Question 3.

445 × 22

Solution:

Question 4.

269 × 36

Solution:

Question 5.

368 × 19

Solution:

Question 6.

145 × 68

Solution:

Question 7.

150 × 59

Solution:

Question 8.

4639 × 2

Solution:

Question 9.

1569 × 6

Solution:

Question 10.

1179 × 8

Solution:

Question 11.

1988 × 5

Solution:

Question 12.

5000 × 2

Solution:

Question 13.

303 × 31

Solution:

Question 14.

425 × 17

Solution:

Question 15.

706 × 12

Solution:

Question 16.

308 × 28

Solution:

2. Find product using expanded notation method:

Question 1.

52 × 7

Solution:

52 × 7 = (50 + 2) × 7

= 50 × 7 + 2 × 7

= 350 + 14

= 364.

Question 2.

63 × 4

Solution:

63 × 4 = (60 + 3) × 4

= 60 × 4 + 3 × 4

= 240 + 12

= 252

Question 3.

81 × 9

Solution:

81 × 9 = (80 + 1) × 9

= 80 × 9 + 1 × 9

= 720 + 9

= 729

Question 4.

123 × 5

Solution:

123 × 5 = (100 + 20 + 3) × 5

= 100 × 5 + 20 × 5 + 3 × 5

= 500 + 100 + 15

= 615

Question 5.

205 × 6

Solution:

205 × 6 = (200 + 5) × 6

= 200 × 6 + 5 × 6

= 1200 + 30

= 1230

3. Find product using Lattice algorithm.

Question 1.

43 × 15

Solution:

Step 1: 43 × 1 (Shown in picture).

Step 2 : 43 × 5 (Shown in picture).

Step 3 : Add diagonally.

Question 2.

426 × 35

Solution:

Step 1: 426 × 3 (Shown in picture).

Step 2 : 426 × 5 (Shown in picture).

Step 3 : By adding diagonal elements

we got 1, 4, 9, 1, 0. which gives us no.

14910.

₹ 426 × 35 = 14910.