PSEB 8th Class Maths Solutions Chapter 15 Introduction to Graphs Ex 15.1

Punjab State Board PSEB 8th Class Maths Book Solutions Chapter 15 Introduction to Graphs Ex 15.1 Textbook Exercise Questions and Answers.

PSEB Solutions for Class 8 Maths Chapter 15 Introduction to Graphs Ex 15.1

1. The following graph shows the temperature of a patient in a hospital, recorded every hour:
PSEB 8th Class Maths Solutions Chapter 15 Introduction to Graphs Ex 15.1 1

Question (a)
What was the patient’s temperature at 1 p.m.?
Solution:
The patient’s temperature at 1 p.m. was 36.5 °C.

PSEB 8th Class Maths Solutions Chapter 15 Introduction to Graphs Ex 15.1

Question (b)
When was the patient’s temperature 38.5 °C?
Solution:
The patient’s temperature was 38.5 °C at 12 noon.

Question (c)
The patient’s temperature was the same two times during the period given. What were these two times?
Solution:
The patient’s temperature was same (36.5 °C) at 1 p.m. and 2 p.m.

Question (d)
What was the temperature at 1:30 p.m.? How did you arrive at your answer?
Solution:
The patient’s temperature at 1:30 p.m. was 36.5 °C.
(The temperature did not change during interval of 1 p.m. and 2 p.m. So the temperature did not show any change and it was 36.5 °C at 1:30 p.m.)

Question (e)
During which periods did the patients’ temperature showed an upward trend?
Solution:
The patient’s temperature showed an upward trend during the periods 9 a.m. to 10 a.m., 10 a.m. to 11a.m. and 2 p.m. to 3 p.m., because the temperature increased during these intervals.

PSEB 8th Class Maths Solutions Chapter 15 Introduction to Graphs Ex 15.1

2. The following line graph shows the yearly sales figures for a manufacturing company:
PSEB 8th Class Maths Solutions Chapter 15 Introduction to Graphs Ex 15.1 2

Question (a)
What were the sales in (i) 2002 (ii) 2006?
Solution:
1. The sales in the year 2002 was ₹ 4 crores.
2. The sales in the year 2006 was ₹ 8 crores.

PSEB 8th Class Maths Solutions Chapter 15 Introduction to Graphs Ex 15.1

Question (b)
What were the sales in (i) 2003 (ii) 2005?
Solution:
1. The sales in the year 2003 was ₹ 7 crores.
2. The sales in the year 2005 was ₹ 10 crores.

Question (c)
Compute the difference between the sales in 2002 and 2006.
Solution:
The difference between the sales in 2002 and 2006 = ₹ (8 – 4) crore
= ₹ 4 crores

Question (d)
In which year was there the greatest difference between the sales as compared to its previous year?
Solution:
In year 2005, there was the greatest difference between the sales as compared to its previous year.

3. For an experiment in Botany, two different plants, plant A and plant B were grown under similar laboratory conditions. Their heights were measured at the end of each week for 3 weeks. The results are shown by the following graph:
PSEB 8th Class Maths Solutions Chapter 15 Introduction to Graphs Ex 15.1 3

Question (a)
How high was Plant A after
1. 2 weeks
2. 3 weeks?
Solution:
1. The plant A was 7 cm high after 2 weeks.
2. The plant A was 9 cm high after 3 weeks.

PSEB 8th Class Maths Solutions Chapter 15 Introduction to Graphs Ex 15.1

Question (b)
How high was Plant B after
1. 2 weeks
2. 3 weeks?
Solution:
1. The plant B was 7 cm high after 2 weeks.
2. The plant B was 10 cm high after 3 weeks.

Question (c)
How much did Plant A grow during the 3rd week?
Solution:
Plant A grew (9 cm – 7 cm) = 2 cm during 3rd week.

Question (d)
How much did Plant B grow from the end of the 2nd week to the end of the 3rd week?
Solution:
The plant B grew (10cm-7cm) = 3 cm from the end of 2nd week to the end of 3rd week.

Question (e)
During which week did Plant A grow most?
Solution:
The growth of the plant A During the 1st week = 2 cm – 0 cm = 2 cm
During the 2nd week = 7 cm – 2 cm = 5 cm
During the 3rd week = 9 cm – 7 cm = 2 cm
Thus, during the 2nd week, the plant A grew the most.

PSEB 8th Class Maths Solutions Chapter 15 Introduction to Graphs Ex 15.1

Question (f)
During which week did Plant B grow least?
Solution:
The growth of the plant B.
During the 1st week = 1cm – 0 cm
= 1 cm
During the 2nd week = 7 cm – 1 cm
= 6 cm
During the 3rd week = 10 cm-7 cm
= 3 cm
Thus, the plant B grew the least in the first week.

Question (g)
Were the two plants of the same height during any week shown here? Specify.
Solution:
At the end of 2nd week, both the plants were of the same height, that is 7 cm.

4. The following graph shows the temperature forecast and the actual temperature for each day of a week.
PSEB 8th Class Maths Solutions Chapter 15 Introduction to Graphs Ex 15.1 4

Question (a)
On which days was the forecast temperature the same as the actual temperature?
Solution:
The forecast temperature was the same as the actual temperature on Tuesday, Friday and Sunday.

PSEB 8th Class Maths Solutions Chapter 15 Introduction to Graphs Ex 15.1

Question (b)
What was the maximum forecast temperature during the week?
Solution:
The maximum forecast temperature during the week was 35 °C.

Question (c)
What was the minimum actual temperature during the week?
Solution:
The minimum actual temperature during the week was 15 °C.

Question (d)
On which day did the actual temperature differ the most from the forecast temperature?
Solution:
On Thursday, the actual temperature differed the most from the forecast temperature (7.5 °C).

Difference of temperature:

  • Monday : 17.5 °C – 15 °C = 2.5 °C
  • Tuesday : 20 °C – 20 °C = o°c
  • Wednesday : 30 °C – 25 °C = 5°C
  • Thursday : 22.5 °C – 15 °C = 7.5 °C
  • Friday : 15 °C – 15 °C = o°c
  • Saturday : 30 °C – 25 °C = 5°C
  • Sunday : 35 °C – 35 °C = o°c

5. Use the tables below to draw linear graphs:

Question (a)
The number of days a hillside city received snow in different years:

Year 2003 2004 2005 2006
Days 8 10 5 12

Solution:
Linear graph to show snowfall in different years:
PSEB 8th Class Maths Solutions Chapter 15 Introduction to Graphs Ex 15.1 5

PSEB 8th Class Maths Solutions Chapter 15 Introduction to Graphs Ex 15.1

Question (b)
Population (in thousands) of men and women in a village in different years:

Year 2003 2004 2005 2006 2007
Number of Men 12 12.5 13 13.2 13.5
Number of Women 11.3 11.9 13 13.6 12.8

Solution:
Draw two perpendicular lines on the graph paper. Take year along X-axis (horizontal line) and population (in thousand) along Y-axis (vertical line).
For men: Mark the points (2003, 12), (2004, 12.5); (2005, 13); (2006, 13.2) and (2007, 13.5) and join them.
For women: Mark the points (2003, 11.3); (2004, 11.9); (2005, 13); (2006, 13.6) and (2007, 12.8) and join them.
PSEB 8th Class Maths Solutions Chapter 15 Introduction to Graphs Ex 15.1 6

PSEB 8th Class Maths Solutions Chapter 15 Introduction to Graphs Ex 15.1

6. A courier cycles from a town to a neighboring suburban area to deliver a parcel to a merchant. His distance from the town at different times is shown by the following graph:
PSEB 8th Class Maths Solutions Chapter 15 Introduction to Graphs Ex 15.1 7

Question (a)
What is the scale taken for the time axis?
Solution:
The time is taken along the X-axis. The scale along X-axis is 4 units = 1 hour.

Question (b)
How much time did the person take for the travel?
Solution:
Total travel time taken by a courier : = 8:00 am to 11:30 am = 3\(\frac {1}{2}\) hours

Question (c)
How far is the place of the merchant from the town?
Solution:
Distance of the merchant from the town is 22 km.

Question (d)
Did the person stop on his way? Explain.
Solution:
Yes, the stopage time = 10:00 am to 10:30 am. This is indicated by the horizontal part of the graph.

Question (e)
During which period did he ride fastest?
Solution:
He rode fastest between 8:00 am and 9:00 am.

PSEB 8th Class Maths Solutions Chapter 15 Introduction to Graphs Ex 15.1

7. Can there be a time-temperature graph as follows? Justify your answer.
PSEB 8th Class Maths Solutions Chapter 15 Introduction to Graphs Ex 15.1 8
Solution:
In case of (iii), the graph shows different number of temperatures at the same time which is not possible.
∴ Case (iii) does not represent a time-temperature graph.

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