Punjab State Board PSEB 5th Class Maths Book Solutions Chapter 9 Volume Ex 9.1 Textbook Exercise Questions and Answers.

## PSEB Solutions for Class 5 Maths Chapter 9 Volume Ex 9.1

1. Find the volume of the following by counting the number of cubes.

Question 1.

Volume = _________

Solution:

Volume = 4 cm^{3}

Question 2.

Volume = _________

Solution:

Volume = 30 cm^{3}

Question 3.

Volume = _________

Solution:

Volume = 36 cm^{3}

2. Complete the table :

Solution:

(i) 6 cm^{3}

(ii) 24 mm^{3}

(iii) 6000 m^{3}

(iv) 343 cm^{3}

(v) 400 m^{3}

3. Find the volume of cube whose side (edge) is :

Question 1.

6 cm

Solution:

Side (edge) of cube = 6 cm

Volume of cube = side × side × side

= 6 cm × 6 cm × 6 cm

= 216 cm^{3}

Question 2.

8 m

Solution:

Side of cube = 8 m

Volume of cube = side × side × side

= 8m × 8m × 8m

= 512 m^{3}

Question 3.

15 mm

Solution:

Side of cube = 15 mm

Volume of cube = side × side × side

= 15 mm × 15 mm × 15 mm

= 3375 mm^{3}

Question 4.

21 m

Solution:

Side of cube = 21m

Volume of cube= side × side × side

= 21 m × 21 m × 21 m

= 9261 m^{3}

4. Find the volume of cuboid whose length, breadth and height is as follows :

Question 1.

9 cm, 6 cm, 3 cm

Solution:

Length of cuboid = 9 cm

Breadth of cuboid = 6 cm

Height of cuboid = 3 cm

Volume of cuboid = Length × Breadth × Height

= 9 cm × 6 cm × 3 cm

= 162 cm^{3}

Question 2.

12 mm, 9 mm, 4 mm

Solution:

Length of cuboid = 12 mm

Breadth of cuboid = 9 mm

Height of cuboid = 4 mm

Volume of cuboid = Length × Breadth × Height

= 12 mm × 9 mm × 4 mm

= 432 mm^{3}

Question 3.

15 m, 13 m, 12 m

Solution:

Length of cuboid = 15 m

Breadth of cuboid = 13 m

Height of cuboid = 12 m

Volume of cuboid = Length × Breadth × Height

= 15 m × 13 m × 12 m

= 2340 m^{3}

Question 4.

22 mm, 16 mm, 12 mm

Solution:

Length of cuboid = 22 mm

Breadth of cuboid = 16 mm

Height of cuboid = 12 mm

Volume of cuboid = Length × Breadth × Height

= 22 mm × 16 mm × 12 mm

= 4224 mm^{3}

Question 5.

25 m, 23 m, 21 m.

Solution:

Length of cuboid = 25 m

Breadth of cuboid = 23 m

Height of cuboid = 21 m

Volume of cuboid = Length × Breadth × Height

= 25 m × 23 m × 21 m

= 12075 m^{3}

Question 5.

A chalk box is 8 cm long, 6 cm broad and 10 cm high. Find the volume of the box.

Solution:

Length of the chalk box = 8 cm

Breadth of the chalk box = 6 cm

Height of the chalk box = 10 cm

Volume of the chalk box = Length × Breadth × Height

= 8 cm × 6 cm × 10 cm

= 480 cm^{3}

Question 6.

A cardboard box is 50 cm long, 40 cm wide and 24 cm high. Find the volume of the box.

Solution:

Length of the cardboard box = 50 cm

Breadth of the cardboard box = 40 cm

Height of the cardboard box = 24 cm

Volume of the cardboard box = Length × Breadth × Height

= 50 cm × 40 cm × 24 cm

= 48000 cm^{3}

Question 7.

Jashan’s tiffin box is 15 cm long, 10 cm wide and 8 cm high and Gurwinder’s tiffin box is 12 cm long, 10 cm wide and 10 cm high. Find the volume of both. Whose tiffin box has more volume ?

Solution:

Jashan :

Length of the tiffin box = 15 cm

Breadth of the tiffin box = 10 cm

Height of the tiffin box = 8 cm

Volume of the tiffin box = Length × Breadth × Height

= 15 cm × 10 cm × 8 cm

= 1200 cm^{3}

Gurwinder :

Length of the tiffin box = 12 cm

Breadth of the tiffin box = 10 cm

Height of the tiffin box = 10 cm

Volume of the tiffin box = Length × Breadth × Height

= 12 cm × 10 cm × 10 cm

= 1200 cm^{3}

Their tiffin boxes have equal volumes.

Question 8.

Find the volume of 25 cuboidal boxes with dimensions 12 cm long, 9 cm wide and 6 cm high each.

Solution:

Length of the cuboidal box =12 cm

Breadth of the cuboidal box = 9 cm

Height of the cuboidal box = 6 cm

Volume of the cuboidal box = Length × Breadth × Height

= 12 cm × 9 cm × 6 cm

= 648 cm^{3}

Volume of 25 cuboidal boxes

= 648 × 25 cm^{3}

= 16200 cm^{3}

Question 9.

There are two types of powder boxes available in the market. One is of cubical shape with side 8 cm and other is of cuboidal shape with length 15 cm, breadth 8 cm and height 4 cm. Which box has more powder and how much? If both have same prices then which box will you prefer?

Solution:

Side of the cubical box = 8 cm

Volume of the cubical box = side x side x side

= 8 cm × 8 cm × 8 cm

= 512 cm^{3}

Length of the cuboidal box = 15 cm

Breadth of the cuboidal box = 8 cm

Height of the cuboidal box = 4 cm

Volume of the cuboidal box = Length × Breadth × Height

= 15 cm × 8 cm × 4 cm

= 480 cm^{3}

Cubical box has more powder

= 512 cm^{3} – 480 cm^{3}

= 32 cm^{3}

I will prefer cubical box.

Question 10.

How many bricks of size 24 cm long, 12 cm wide and 8 cm thick are required for* making a wall of 12 m long, 3 m high and 24 cm thick?

Solution:

Length of the wall = 12 m

= 12 × 100 cm

= 1200 cm

Height of the wall = 3 m

= 3 × 100 cm

= 300 cm

Breadth of the wall = 24 cm

Volume of the wall = Length × Breadth × Height

= 1200 cm × 24 cm × 300 cm

= 8640000 cm^{3}

Length of each brick = 24 cm

Breadth of each brick = 12 cm

Height of each brick = 8 cm

Volume of each brick = Length × Breadth × Height

= 24 cm × 12 cm × 8 cm

= 2304 cm^{3}

Number of bricks required

= \(\frac{8640000 \mathrm{~cm}^{3}}{2304 \mathrm{~cm}^{3}}\)

= 3750 bricks.

Question 11.

The length, breadth and height of a biscuit packet is 15 cm, 9 cm and 6 cm respectively. If a packet has 30 biscuits then Bind the volume of each biscuit.

Solution:

Length of the packet = 15 cm

Breadth of the packet = 9 cm

Height of the packet = 6 cm

Volume of the packet = Length × Breadth× Height

= 15 cm × 9 cm × 6 cm

= 810 cm^{3}

Total number of biscuits in the packet = 30

Volume of each biscuit = \(\frac{810 \mathrm{~cm}^{3}}{30}\)

= 27 cm^{3}

Question 12.

One trolley is full of bricks. It is 4 m long, 2 m wide and 60 cm deep. One brick is of size 20 cm x 10 cm x 6 cm. How many bricks are there in the trolley ?

Solution:

Length of the trolley

= 4m = 4 × 100 cm = 400 cm

Breadth of the trolley

= 2 m = 2 × 100 cm = 200 cm

Depth (Height) of the trolley = 60 cm

Volume of the trolley = Length × Breadth × Depth

= 400 cm × 200 cm × 60 cm

= 4800000 cm^{3}

Length of the brick = 20 cm

Breadth of the brick = 10 cm

Height of the brick = 6 cm

Volume of the brick = Length × Breadth × Height

= 20 cm × 10 cm × 6 cm

= 1200 cm^{3}

Number of bricks in the trolley

= \(\frac{4800000}{1200}\) cm^{3}

= 4000.

13. Fill in the blanks :

Question 1.

Volume of cube = __________ × __________ × ________

Solution:

Side × Side × Side

Question 2.

Volume of cuboid = __________ × __________ × ________

Solution:

Length × Breadth × Height

Question 3.

The space occupied by a solid is called its ________

Solution:

Volume.