Punjab State Board PSEB 6th Class Maths Book Solutions Chapter 2 Whole Numbers Ex 2.2 Textbook Exercise Questions and Answers.

## PSEB Solutions for Class 6 Maths Chapter 2 Whole Numbers Ex 2.2

1. Find the sum by suitable arrangement of terms:

Question (a)

837 + 208 + 363

Solution:

837 + 208 + 363

= (837 + 363) + 208

= 1200 + 208

= 1408

Question (b)

1962 + 453 + 1538 + 647.

Solution:

1962 + 453 + 1538 + 647

= (1962 + 1538) + (453 + 647)

= 3500 + 1100

= 4600

2. Find the product by suitable arrangement of terms:

Question (a)

2 × 1497 × 50

Solution:

= (2 × 50) × 1497

= 100 × 1497

= 149700

Question (b)

4 × 263 × 25

Solution:

= (4 × 25) × 263

= 100 × 263

= 26300

Question (c)

8 × 163 × 125

Solution:

= (8 × 125) × 163

= 1000 × 163

= 163000

Question (d)

963 × 16 × 25

Solution:

= 963 × (16 × 25)

= 963 × 400

= 385200

Question (e)

5 × 171 × 60

Solution:

= (5 × 60) × 171

= 300 × 171

= 51300

Question (f)

125 × 40 × 8 × 25

Solution:

= (125 × 40) × (8 × 25)

= 5000 × 200

= 1000000

Question (g)

30921 × 25 × 40 × 2

Solution:

= 30921 × (25 × 40) × 2

= 30921 × 1000 × 2

= 61842000

Question (h)

4 × 2 × 1932 × 125

Solution:

4 × 2 × 1932 × 125

= 1932 × (4 × 2 × 125)

= 1932 × 1000

= 1932000

Question (i)

5462 × 25 × 4 × 2.

Solution:

= 5462 × 2 × 25 × 4

= 10924 × 100

= 1092400

3. Find the value of each of the following using distributive property:

Question (a)

(649 × 8) + (649 × 2)

Solution:

(649 × 8) + (649 × 2)

= 649 × (8 + 2)

= 649 × 10

= 6490

Question (b)

(6524 × 69) + (6524 × 31)

Solution:

(6524 × 69) + (6524 × 31)

= 6524 × (69 + 31)

= 6524 × 100

= 652400

Question (c)

(2986 × 35) + (2986 × 65)

Solution:

(2986 × 35) + (2986 × 65)

= 2986 × (35 + 65)

= 2986 × 100

= 298600

Question (d)

(6001 × 172) – (6001 × 72).

Solution:

(6001 × 172) – (6001 × 72)

= 6001 × (172 – 72)

= 6001 × 100

= 600100

4. Find the value of the following:

Question (a)

493 × 8 + 493 × 2

Solution:

(a) 493 × 8 + 493 × 2

= 493 × (8 + 2) = 493 × 10

= 4930

Question (b)

24579 × 93 + 7 × 24579

Solution:

24579 × 93 + 7 × 24579

= 24579 × (93 + 7)

= 24579 × 100

= 2457900

Question (c)

3845 × 5 × 782 + 769 × 25 × 218

Solution:

3845 × 5 × 782 + 769 × 25 × 218

= 769 × 5 × 5 × 782 + 769 × 5 × 5 × 218

= 769 × 5 × 5 × (782 + 218)

= 769 × 25 × 1000

= 19225 × 1000

= 19225000

Question (d)

3297 × 999 + 3297.

Solution:

3297 × 999 + 3297

= (3297) × (999 + 1)

= 3297 × 1000

= 3297000

5. Find the product, using suitable properties:

Question (a)

738 × 103

Solution:

= 738 × (100 + 3)

= (738 × 100) + (738 × 3)

[Using a × (b + c) = (a × b) + (a × c)]

= 73800 + 2214

= 76014

Question (b)

854 × 102

Solution:

= 854 × (100 + 2)

= (854 × 100) + (854 × 2)

[Using a × (b + c) = (a × b) + (a × c)]

= 85400 + 1708

= 87108

Question (c)

258 × 1008

Solution:

= 258 × (1000 + 8)

= (258 × 1000) + (258 x 8)

[Using a × (b + c) = (a × b) + (a × c)]

= 258000 + 2064

= 260064

Question (d)

736 × 93

Solution:

= 736 × (100 – 7)

= 736 × 100 = 736 × 7

[Using a × (b – c) = (a × b) – (a × c)]

= 73600 – 5152

= 68448

Question (e)

816 × 745

Solution:

= (800 + 16) × 745

= 800 × 745 + 16 × 745

[Using a × (b + c) = (a × b) + (a × c)]

= 596000 + 11920

= 607920

Question (f)

2032 × 613

Solution:

= 2032 × (600 + 13)

= 2032 × 600 + 2032 × 13

[Using a × (b + c) = (a × b) + (a × c)]

= 1219200 + 26416

= 1245616

6. A taxi driver filled his car petrol tank with 40 litres of petrol on Monday. The next day, he filled the tank with 50 litres of petrol. If the petrol costs ₹ 78 per litre, how much he spend in all on petrol?

Solution:

Petrol filled on Monday = 40 Litres

Petrol filled on Tuesday = 50 Litres

Total Petrol filled = 40 + 50 = 90 Litres

Cost per litre = ₹ 78

Total Cost = 90 × ₹ 78

= ₹ 7020

7. A vendor supplies 32 litres of milk to a hotel in the morning and 68 litres of milk in the evening. If the milk costs ₹ 35 per litre, how much money is due to the vendor per day?

Solution:

Milk supplied in the morning = 32 Litres

Milk supplied in the evening = 68 Litres

Total milk supplied = 32 + 68

= 100 Litres

Cost Per litre = ₹ 35

∴ Total cost of milk per day = 100 × ₹ 35

= ₹ 3500

8. We know that 0 × 0 = 0. Is there any other whole number which when multiplied by itself gives the product equal to the number itself? Find out the number.

Solution:

Yes, there is a whole number 1.

Here 1 × 1 = 1.

9. Fill in the blanks:

Question (i)

(a) 15 × 0 = ………….. .

(b) 15 + 0 = ………….. .

(c) 15 – 0 = ………….. .

(d) 15 ÷ 0 = ………….. .

(e) 0 × 15 = ………….. .

(f) 0 + 15 = ………….. .

(g) 0 ÷ 15 = ………….. .

(h) 15 × 1 = ………….. .

(i) 15 ÷ 1 = ………….. .

(j) 1 ÷ 1 = ………….. .

Solution:

(a) 0,

(b) 15,

(c) 15,

(d) Not defined,

(e) 0,

(f) 15,

(g) 0,

(h) 15,

(i) 15,

(j) 1.

Question 10.

The product of two Whole numbers is zero. What do you conclude. Explain with example.

Solution:

We conclude that one number must be zero such 25 × 0 = 0.

Question 11.

Match the following:

1. 537 × 106 = 537 ×100 + 537 × 6 | (a) Commutativity under multiplication |

2. 4 × 47 × 25 = 4 × 25 × 47 | (b) Commutativity under addition |

3. 70 + 1923 + 30 = 70 + 30 + 1923 | (c) Distributivity of multiplication over addition. |

Solution:

1. 537 × 106 = 537 × 100 + 537 × 6 | (c) Distributivity of multiplication over addition. |

2. 4 × 47 × 25 = 4 × 25 × 47 | (a) Commutativity under multiplication |

3. 70 + 1923 + 30 = 70 + 30 + 1923 | (b) Commutativity under addition |