PSEB 5th Class Maths Solutions Chapter 4 Fractions Ex 4.3

Punjab State Board PSEB 5th Class Maths Book Solutions Chapter 4 Fractions Ex 4.3 Textbook Exercise Questions and Answers.

PSEB Solutions for Class 5 Maths Chapter 4 Fractions Ex 4.3

Question 1.
Check whether the following fractions are equivalent or not :
(a) \(\frac{3}{7}\) and \(\frac{6}{14}\)
(b) \(\frac{11}{14}\) and \(\frac{77}{98}\)
(c) \(\frac{6}{9}\) and \(\frac{24}{36}\)
(d) \(\frac{5}{8}\) and \(\frac{10}{24}\)
(e) \(\frac{7}{12}\) and \(\frac{14}{21}\)
(f) \(\frac{8}{9}\) and \(\frac{40}{54}\)
Solution:
(a) Numerator of first fraction × Denominator of second fraction
= 3 × 14 = 42
Denominator of first fraction × Numerator of second fraction
= 7 × 6 = 42
Both the products are equal. So these fractions are equivalent.

(b) Numerator of first fraction × Deno-minator of second fraction
= 11 × 98 = 1078
Denominator of first fraction × Num-erator of second fraction
= 14 × 77 = 1078
Both the products are equal, so these fractions are equivalent.

PSEB 5th Class Maths Solutions Chapter 4 Fractions Ex 4.3

(c) Numerator of first fraction × Denominator of second fraction
= 6 × 36 = 216
Denominator of first fraction × Numerator of second fraction
= 9 × 24 = 216
Both the products are equal, so these fractions are equivalent.

(d) Numerator of first fraction × Denominator of second fraction
= 5 × 24 = 120
Denominator of first fraction × Numerator of second fraction
= 8 × 10 = 80
Both the products are not equal, so these fractions are not equivalent.

(e) Numerator of first fraction × Denominator of second fraction
= 7 × 21 = 147
Denominator of first fraction × Numerator of second fraction
= 12 × 14= 168
Both the products are not equal, so these fractions are not equivalent.

(f) Numerator of first fraction × Denominator of second fraction.
= 8 × 54 = 432
Denominator of first fraction × Numerator of second fraction
= 9 × 40 = 360
Both the products are not equal, so these fractions are not equivalent.

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