Bhagya – Page 2 – PSEB Solutions

PSEB 9th Class Maths Solutions Chapter 4 Linear Equations in Two Variables Ex 4.2

April 2, 2024April 1, 2024 by Bhagya

Punjab State Board PSEB 9th Class Maths Book Solutions Chapter 4 Linear Equations in Two Variables Ex 4.2 Textbook Exercise Questions and Answers.

PSEB Solutions for Class 9 Maths Chapter 4 Linear Equations in Two Variables Ex 4.2

Question 1.
Which one of the following options is true, and why?
y = 3x + 5 has
(i) a unique solution,
(ii) only two solutions,
(iii) infinitely many solutions.
Answer:
Option (iii) is true. Since y = 3x + 5 is a linear equation in two variables, it has infinitely many solutions. e.g., (1, 8), (2, 11), (3, 14), (4, 17), (0, 5), (- 1, 2) are all solutions of the given equation y = 3x + 5.

Question 2.
Write four solutions for each of the following equations:
(i) 2x + y = 7
Answer:
2x + y = 7
∴ y = 7 – 2x
Taking x = 0, 1, 2, 3, we get the values of y as 7, 5, 3 and 1 respectively. Thus, (0, 7), (1, 5), (2, 3) and (3, 1) are four solutions of the given equation 2x + y = 7. We can give other answers as well because the given linear equation in two variables has infinitely many solutions.

(ii) πx + y = 9
Answer:
πx + y = 9
∴ y = 9 – πx
For x = 0, y = 9.
For x = 1, y = 9 – π.
For x = – 1, y = 9 + π.
For x = , y = 8.
Thus, (0, 9), (1, 9 – π), (- 1, 9 + π) and (\(\frac{1}{\pi}\), 8) are four of the infinitely many solutions of the given equation πx + y = 9.

(iii) x = 4y
Answer:
x = 4y
For y = 0, x = 0.
For y = 1, x = 4.
For y = – 1, x = – 4.
For y = 2, x = 8.
Thus, (0, 0), (4, 1), (- 4, – 1) and (8, 2) are four of the infinitely many solutions of the given equation x = 4y.

Question 3.
Check which of the following are solutions of the equation x – 2y = 4 and which are not:
(i) (0, 2)
Answer:
Substituting x = 0 and y = 2, we get x – 2y = 0 – 2(2) = – 4, which is not equal to 4. Hence, (0, 2) is not a solution of x – 2y = 4.

(ii) (2, 0)
Answer:
Substituting x = 2 and y = 0, we get x – 2y = 2 – 2 (0) = 2, which is not equal to 4. Hence, (2, 0) is not a solution of x – 2y = 4.

(iii) (4, 0)
Answer:
Substituting x = 4 and y = 0, we get x – 2y = 4 – 2 (0) = 4. Hence, (4, 0) is a solution of x – 2y = 4.

(iv) (√2, 4√2)
Answer:
Substituting x = √2 and y = 4√2, we get x – 2y = √2 – 2(4√2) = – 7√2, which is not equal to 4. Hence, (√2, 4√2) is not a solution of x – 2y = 4.

(v) (1, 1)
Answer:
Substituting x = 1 and y = 1, we get x – 2y = 1 -2(1) = – 1, whIch is not equal to 4. Hence, (1, 1) is not a solution of x – 2y = 4.

Question 4.
Find the value of k, if x = 2, y = 1 is a solution of the equation 2x + 3y = k.
Answer:
x = 2, y = 1 is a solution of equation 2x + 3y = k. Hence, x = 2 and y = 1 satisfy the equation.
∴ 2(2) + 3(1) = k
∴ 4 + 3 = k
∴ 7 = k
∴ k = 7

PSEB 9th Class Maths Solutions Chapter 4 Linear Equations in Two Variables Ex 4.1

April 2, 2024April 1, 2024 by Bhagya

Punjab State Board PSEB 9th Class Maths Book Solutions Chapter 4 Linear Equations in Two Variables Ex 4.1 Textbook Exercise Questions and Answers.

PSEB Solutions for Class 9 Maths Chapter 4 Linear Equations in Two Variables Ex 4.1

Question 1.
The cost of a notebook is twice the cost of a pen. Write a linear equation in two variables to represent this statement.
(Take the cost of a notebook to be and that of a pen to be ₹ y.)
Answer:
Let the cost of a notebook be ₹ x and the cost of a pen be ₹ y.
Then, according to the given data, the cost of a notebook is twice the cost of a pen.
∴ x = 2y
Thus, x = 2y, i.e., x – 2y = 0 is the required linear equation in two variables.

Question 2.
Express the following linear equations in the form ax + by + c = 0 and indicate the values of a, b and c in each case:
(i) 2x + 3y = 9.3\(\overline{5}\)
Answer:
2x + 3y = 9.3\(\overline{5}\)
∴ 2x + 3y – 9.3\(\overline{5}\) = 0
Here, a = 2, b = 3 and c = – 9.3\(\overline{5}\).

(ii) x – \(\frac{y}{5}\) – 10 = 0
Answer:
x – \(\frac{y}{5}\) – 10 = 0
∴x – \(\frac{1}{5}\)y – 10 = 0
Here, a = 1, b = – \(\frac{1}{5}\) and c = – 10.

(iii) – 2x + 3y = 6
Answer:
– 2x + 3y = 6
∴ – 2x + 3y – 6 = 0
Here, a = 1, b = – 3 and c = – 6.

(iv) x = 3y
Answer:
x = 3y
∴ x – 3y + 0 = 0
Here, a = 1, b = – 3 and c = 0.

(v) 2x = – 5y
Answer:
2x = – 5y
∴ 2x + 5y + 0 = 0
Here, a = 2, b = 5 and c = 0

(vi) 3x + 2 = 0
Answer:
3x + 2 = 0
∴ 3x + oy – 2 = 0
Here, a = 3, b = 1 and c = – 2

(vii) y – 2 = 0
Answer:
y – 2 = 0
∴ 0x + y – 2= 0
Here a = 0, b = 1 and c = – 2

(viii) 5 = 2x
Answer:
5 = 2x
∴ 5 – 2x = 0
∴ – 2x + 0y + 5 = 0
Here a = – 2, b = 0, c = 5

PSEB 6th Class Maths Solutions Chapter 3 Playing with Numbers Ex 3.2

April 2, 2024April 1, 2024 by Bhagya

Punjab State Board PSEB 6th Class Maths Book Solutions Chapter 3 Playing with Numbers Ex 3.2 Textbook Exercise Questions and Answers.

PSEB Solutions for Class 6 Maths Chapter 3 Playing with Numbers Ex 3.2

1. Find the common factors of the followings:

Question (i)
16 and 24
Solution:
The factors of 16
= 1, 2, 4, 8, 16
The factors of 24
= 1, 2, 3, 4, 6, 8, 12, 24
Common factors of 16 and 24
= 1, 2, 4, 8

Question (ii)
25 and 40
Solution:
The factors of 25
= 1, 5, 25
The factors of 40
= 1, 2, 4, 5, 8, 10, 20, 40
Common factors of 25 and 40
= 1, 5

Question (iii)
24 and 36
Solution:
The factors of 24
= 1, 2, 3, 4, 6, 8, 12, 24
The factors of 36
= 1, 2, 3, 4, 6, 12, 18, 36
Common factors of 24 and 36
= 1, 2, 3, 4, 6, 12

Question (iv)
14, 35 and 42
Solution:
The factors of 14
= 1, 2, 7, 14
The factors of 35
= 1, 5, 7, 35
The factors of 42
= 1,2,3, 6, 7, 21, 42
Common factors of 14, 35 and 42
= 1, 7

Question (v)
15, 24 and 35.
Solution:
The factors of 15
= 1, 3, 5, 15
The factors of 24
= 1, 2, 3, 4, 6, 8, 12, 24
The factors of 35
= 1, 5, 7, 35
Common factors of 15, 24 and 35.
= 1

2. Find first three common multiples of the followings:

Question (i)
3 and 5
Solution:
The multiples of 3
= 3, 6, 9, 12, 15, 18, 21, 24, 27, 30, 33, 36, 39, 42, 45
The multiples of 5
= 5, 10, 15, 20, 25, 30, 35, 40,45
First three common multiples of 3 and 5
= 15, 30 and 45

Question (ii)
6 and 8
Solution:
The multiples of 6
= 6, 12, 18, 24, 30, 36, 42, 48 54, 60, 66, 72
The multiples of 8
= 8, 16, 24, 32, 40, 48, 56, 64, 72
First three common multiples of 6 and 8
= 24, 48 and 72

Question (iii)
2, 3 and 4.
Solution:
The multiples of 2
= 2, 4, 6, 8, 10, 12, 14, 16, 18, 20, 22, 24, 26, 28, 30, 32, 34, 36
The multiples of 3
= 3, 6, 9, 12, 15, 18, 21, 24, 27, 30, 33, 36
The multiples of 4
= 4, 8, 12, 16, 20, 24, 28, 32, 36
First three common multiples of 2, 3 and 4
= 12, 24 and 36

3. Which of the following numbers are divisible by 2 or 4?

Question (i)
52314
Solution:
52314 is divisible by 2 as it is even number.
52314 is not divisible by 4 because the last two digits i.e. 14 which is not divisible by 4

Question (ii)
678913
Solution:
678913 is not divisible by 2. As it is an odd number.
678913 is not divisible by 4 because the last two digits i.e. 13 is not divisible by 4.

Question (iii)
4056784
Solution:
4056784 is divisible by 2. As it is an even number.
4056784 is also divisible by 4 because the last two digits i.e. 84 which is divisible by 4.

Question (iv)
21536
Solution:
21536 is divisible by 2. As it is an even number.
21536 is divisible by 4. As number formed by their last two digits is divisible by 4.

Question (v)
412318.
Solution:
412318 is divisible by 2. As it is an even number.
412318. is not divisible by 4. As number formed by their last two digits is not divisible by 4.

4. Which of the following numbers are divisible by 3 or 9?

Question (i)
654312
Solution:
654312 is divisible by 3.
As sum of its digits = 6 + 5 + 4 + 3 + 1 + 2 = 21, which is divisible by 3.
654312 is not divisible by 9.
As sum of its digits = 21, which is not divisible by 9.

Question (ii)
516735
Solution:
516735 is divisible by 3.
As sum of its digits = 5 + 1 + 6 + 7 + 3 + 5 = 27, which is divisible by 3.
516735 is also divisible by 9.
As sum of its digits = 27, which is divisible by 3.

Question (iii)
423152
Solution:
423152 is divisible by 3.
As sum of its digits = 4 + 2 + 3 + 1 + 5 + 2=17, which is not divisible by 3.
423152 is also not divisible by 9.
As sum of its digits = 17, which is not divisible by 9.

Question (iv)
704355
Solution:
704355 is divisible by 3.
As sum of its digits = 7 + 0 + 4 + 3 + 5 + 5 = 24, which is divisible by 3.
704355 is not divisible by 9.
As sum of its digits = 24, which is not divisible by 9.

Question (v)
215478.
Solution:
215478 is divisible by 3.
As sum of its digits = 2 + 1 + 5 + 4 + 7 + 8 = 27, which is divisible by 3.
215478 is divisible by 9.
As sum of its digits = 27, which is divisible by 9.

5. Which of the following numbers are divisible by 5 or 10?

Question (i)
456803
Solution:
456803 is not divisible by 5
As its last digit is not 0 or 5.
456803 is not divisible by 10
As its last digit is not 0.

Question (ii)
654130
Solution:
654130 is divisible by both 5 and 10
As its last digit is 0.

Question (iii)
256785
Solution:
256785 is divisible by 5
As its last digit is 5.
256785 is not divisible by 10
As its last digit is not 0.

Question (iv)
412508
Solution:
412508 is not divisible by 5
As its last digit is not 0 or 5.
412508 is not divisible by 10
As its last digit is not 0.

Question (v)
872565.
Solution:
872565 is divisible by 5
As its last digit is 5.
872565 is not divisible by 10
As its last digit is not 0.

6. Which of the following numbers are divisible by 8?

Question (i)
457432
Solution:
457432 is divisible by 8, because its last three digits are 432, which is divisible by 8.

Question (ii)
5134214
Solution:
5134214 is not divisible by 8, because its last three digits are 214, which is not divisible by 8.

Question (iii)
7232000
Solution:
7232000 is divisible by 8, because its last three digits are 000, which is divisible by 8.

Question (iv)
5124328
Solution:
5124328 is divisible by 8, because its last three digits are 328, which is divisible by 8.

Question (v)
642516.
Solution:
642516 is not divisible by 8, because its last three digits are 516, which is not divisible by 8.

7. Which of the following numbers are divisible by 6?

Question (i)
425424
Solution:
425424 is divisible by 2 because, it has 4 in its units place.
Sum of digits = 4 + 2 + 5+4 + 2 + 4 = 21
Sum of digits of 425424 is divisible by 3.
∴ 425424 is divisible by 2 as well as 3
Hence, 425424 is divisible by 6.

Question (ii)
617415
Solution:
617415 is not divisible by 2 because, it has 5 in its units place.
∴ 617415 is not divisible by 6.

Question (iii)
3415026
Solution:
3415026 is divisible by 2 because, it has 6 in its units place.
Sum of digits = 3 + 4 + 1 + 5 + 0 + 2 + 6 = 21
Sum of digits of 3415026 is divisible by 3
So, 3415026 is divisible by 3
∴ 3415026 is divisible by 2 as well as 3
Hence, 3415026 is divisible by 6.

Question (iv)
4065842
Solution:
4065842 is divisible by 2 because, it has 2 in its units place.
Sum of digits = 4 + 0 + 6 + 5 + 8 + 4 + 2 = 29
Sum of digits of 4065842 is not divisible by 3.
So, 4065842 is not divisible by 3.
∴ 4065842 is divisible by 2 but not by 3.
Hence, 4065842 is not divisible by 6.

Question (v)
725436.
Solution:
725436 is divisible by 2 because, it has 6 in its units place.
Sum of digits = 7 + 2 + 5 + 4 + 3 + 6 = 27
Sum of digits of 725436 is divisible by 3.
So, 725436 is divisible by 3.
∴ 725436 is divisible by 2 as well as 3
Hence, 725436 is divisible by 6.

8. Which of the following numbers are divisible by 11?

Question (i)
4281970
Solution:
4281970 is divisible by 11.
PSEB 6th Class Maths Solutions Chapter 3 Playing with Numbers Ex 3.2 1
Since sum of its digits in odd places = 4 + 8 + 9 + 0 = 21 and
sum of its digits in even places = 2 + 1 + 7 = 10
Their difference = 21 – 10=11, which is odd places digits divisible by 11.

Question (ii)
8049536
Solution:
8049536 is divisible by 11.
PSEB 6th Class Maths Solutions Chapter 3 Playing with Numbers Ex 3.2 2
Since sum of its digits in odd places = 8 + 4 + 5 + 6 = 23
and sum of its digits in even places = 0 + 9 + 3 = 12
Difference = 23 – 12 = 11, which is divisible by 11.

Question (iii)
1234321
Solution:
1234321 is divisible by 11.
PSEB 6th Class Maths Solutions Chapter 3 Playing with Numbers Ex 3.2 3
Since sum of its digits in odd places = 1 + 3 + 3 + 1 = 8
and sum of its digits in even places = 2 + 4 + 2 = 8
Difference = 8 – 8 = 0.

Question (iv)
6450828
Solution:
6450828 is not divisible by 11.
PSEB 6th Class Maths Solutions Chapter 3 Playing with Numbers Ex 3.2 4
Since sum of its digits in odd places = 6 + 5 + 8 + 8 = 27
and sum of its digits in even places = 4 + 0 + 2 = 6
Difference = 27 – 6 = 21, which is not divisible by 11.

Question (v)
5648346.
Solution:
5648346 is divisible by 11.
PSEB 6th Class Maths Solutions Chapter 3 Playing with Numbers Ex 3.2 5
Since sum of its digits in odd places = 5 + 4 + 3 + 6 = 18 and
sum of its digits in even places = 6 + 8 + 4 = 18.
Difference = 18 – 18 = 0.

9. State True or False:

Question (i)
If a number is divisible by 24, then it is also divisible by 3 and 8.
Solution:
True

Question (ii)
60 and 90 both are divisible by 10 then their sum is not divisible by 10.
Solution:
False

Question (iii)
If a number is divisible by 8 then it is also divisible by 16.
Solution:
False

Question (iv)
If a number is divisible by 15 then it is also divisible by 3.
Solution:
True

Question (v)
144 and 72 are divisible by 12 then their difference is also divisible by 12.
Solution:
True

10. If a number is divisible by 5 and 9 then by which other numbers will that number be always divisible?
Solution:
If a number is divisible by 5 and 9. Then the number is also divisible by their product i.e. 5 × 9 = 45.

11. Which of the following pairs are co-prime?

Question (i)
25, 35
Solution:
Two numbers are said to be co-prime if they do not have a common factor other than 1.
Given numbers are 25 and 35 Factors of 25 = 1, 5, 25
Factors of 35 = 1, 5, 7, 35
Since 25 and 35 have 1 and 5 two common factors
∴ 25 and 33 are not co-prime.

Question (ii)
16,21
Solution:
Given numbers are 16 and 21
Factors of 16 = 1, 2, 4, 8, 16
Factors of 21 = 3, 7, 21
There is only 1 common factors 16 and 21 are co-prime
∴ 16 and 21 are co-prime.

Question (iii)
24, 41
Solution:
Given numbers are 24 and 41
Factors of 24 = 1, 2, 3, 4, 6, 8, 12, 24
Factors of 41 = 1, 41
There is only one (1) common factors.
∴ 24 and 41 are co-prime.

Question (iv)
48,33
Solution:
Given numbers are 48 and 33
Factors of 48 = 1, 2, 3, 4, 6, 8, 12, 16, 24, 48
Factors of 33 = 1, 3, 11
There are two common factors 1 and 3.
∴ 48 and 33 are not co-prime.

Question (v)
20, 57.
Solution:
Given numbers are 20 and 57
Factors of 20 = 1, 2, 4, 5, 10, 20
Factors of 57 = 1, 3, 19, 57
There is only only one (1) common factors.
∴ 20 and 57 are co-prime.

PSEB 6th Class Social Science Notes in Punjabi English Medium

April 2, 2024April 1, 2024 by Bhagya

Punjab State Board Syllabus PSEB 6th Class Social Science Notes Pdf in English Medium and Punjabi Medium are part of PSEB Solutions for Class 6.

PSEB 6th Class Social Science Notes in English Medium

PSEB 6th Class Social Science Notes Geography: The Earth – Our Habitat

Chapter 1 Earth – As a Member of Solar System Notes
Chapter 2 Globe – The Model of the Earth Notes
Chapter 3 Motions of the Earth Notes
Chapter 4 How Maps Help Us Notes
Chapter 5 Realms of the Earth Notes
Chapter 6 Our India – In World Notes
Chapter 7 Climate, Vegetation and Wildlife of India Notes (Not in Syllabus)

PSEB 6th Class Social Science Notes History: People and Society in the Ancient Period

Social Science Notes for Class 6 PSEB Civics: Community and its Development

PSEB 6th Class Science Notes Chapter 16 Garbage Management and Disposal

April 2, 2024April 1, 2024 by Bhagya

This PSEB 6th Class Science Notes Chapter 16 Garbage Management and Disposal will help you in revision during exams.

PSEB 6th Class Science Notes Chapter 16 Garbage Management and Disposal

→ Any substance which is no more useful is called waste.

→ Solid waste is called garbage. It is generated by human activities.

→ Garbage has both useful and non-useful components.

→ There are many types of wastes like industrial waste, domestic waste, agricultural waste, biomedical waste, etc.

→ Two types of garbage or solid waste are biodegradable wastes and non-biodegradable waste.

→ For proper disposal of garbage, we must do segregation before disposing of the garbage. We can do this by using differently colored dustbins.

→ To manage the waste there is the 4R’s i.e. reuse, reduce, recycle, refuse.

→ Some parts of the garbage can be reused.

→ Usually, garbage is collected and thrown in landfills.

→ Composting or vermicomposting can be done of useful components or biodegradable components of garbage.

→ Dry leaves, husk of wheat, and part of crops should not be burnt as they produce lots of smoke and harmful gases.

→ Red worms are good for vermicomposting of vegetable and fruit waste, coffee and tea leaves, weeds, etc. but oily, pickled, salty food, and milk products are not good for red worms.

→ Some types of plastics, paper, glass, and metal can be recycled.

→ Plastics bum with a foul smell and produce lots of harmful gases.

→ Plastic bags cause choking of drains and sewer systems.

→ Plastic bags eaten by animals are the cause of their death.

→ Plastic is useful as things made of them last long.

→ The incineration method releases harmful gases and causes pollution.

→ e-waste includes discarded mobiles or any electronic device.

→ Garbage: The solid waste is called garbage.

→ Dump: A large low-lying area used to dispose of garbage.

→ Landfill: A low-lying area to be filled by garbage is a landfill.

→ Biodegradable Waste: Waste material that can be decomposed by the action of microorganisms into harmless substances.

→ Non-biodegradable Waste: The waste materials that cannot be decomposed easily.

→ Incineration: The process of burning waste in closed containers.

→ Compost: The decomposition of organic material into useful material is compost.

→ Vermi-Composting: The method of preparing compost with the help of red worms is vermicomposting.

→ Gizzard: The teeth like hard structures present in red worms for grinding purposes is called the gizzard.

→ Recycling: The process of using a few materials, again and again, is recycling.

PSEB 9th Class Maths MCQ Chapter 3 Coordinate Geometry

April 2, 2024April 1, 2024 by Bhagya

Punjab State Board PSEB 9th Class Maths Book Solutions Chapter 3 Coordinate Geometry MCQ Questions with Answers.

PSEB 9th Class Maths Chapter 3 Coordinate Geometry MCQ Questions

Multiple Choice Questions and Answer

Answer each question by selecting the proper alternative from those given below each question to make the statement true:

Question 1.
For x = 2, y = 3, u = – 2 and v = – 3, point (x + y, u + v) lies in the ……………. quadrant.
A. first
B. second
C. third
D. fourth
Answer:
D. fourth

Question 2.
For x = 4, y = – 5, u = – 6 and v = 8, point (x + y, u + v) lies In the quadrant.
A. first
B. second
C. third
D. fourth
Answer:
B. second

Question 3.
If (x, y) and (y, x) represent the same point in the coordinate plane, then is possible.
A. x = 5, y = 2
B. x = 2, y = 5
C. x = – 5. y = – 2
D. x = 5, y = 5
Answer:
D. x = 5, y = 5

Question 4.
The line Joining P(3, -2) and Q(3, 4)
A. is parallel to the x-axis
B. is parallel to the y-axis
C. is perpendicular to the y-axis
D. intersects both the axes
Answer:
B. is parallel to the y-axis

Question 5.
The line joining A(- 2, 5) and B(- 2, – 8)
A. is parallel to the x-axis
B. is perpendicular to the x-axis
C. intersects the y-axis
D. intersects both the axes
Answer:
B. is perpendicular to the x-axis

Question 6.
The line joining A (- 2, 5) and B (3, 5) intersects ……………….. .
A. the x-axis at (- 2, 0)
B. the x-axis at (3, 0)
C. the y-axis at (0, 5)
D. the x-axis at (5, 0)
Answer:
C. the y-axis at (0, 5)

Question 7.
The line joining A (3, 2) and B (3, – 2) intersects …………………….. .
A. the x-axis at (0, 3)
B. the x-axis at (3, 0)
C. the y-axis at (0, 2)
D. the y-axis at (0, – 2)
Answer:
B. the x-axis at (3, 0)

PSEB 6th Class Science Notes Chapter 15 Air Around Us

April 2, 2024April 1, 2024 by Bhagya

This PSEB 6th Class Science Notes Chapter 15 Air Around Us will help you in revision during exams.

PSEB 6th Class Science Notes Chapter 15 Air Around Us

→ All living things require air to live.

→ Air is present everywhere around us however we cannot see the air.

→ Our earth is surrounded by a thin layer of air that extends upto many kilometres above the surface of the earth. This is known as the atmosphere.

→ Air is made up of water vapours, Oxygen, Nitrogen, Carbon dioxide, dust, and smoke.

→ Nitrogen and Oxygen are the main constituents of air and are present in large quantities.

→ In the air, nitrogen is 78% and oxygen is only 21%.

→ Oxygen is required for burning.

→ Carbon dioxide is a greenhouse gas.

→ The balance of Oxygen and Carbon dioxide in the atmosphere is maintained by the presence of living organisms (man, animals) and plants.

→ Carbon dioxide is used by plants for producing food by photosynthesis. They release oxygen.

→ Oxygen is consumed by animals and humans for respiration. They produce carbon dioxide.

→ Carbon dioxide is used as a fire extinguisher because carbon dioxide does not support g burning.

→ Air can be compressed and it also exerts pressure.

→ Moving air is called wind.

→ Moving air has the power to rotate a windmill which produces electricity.

→ Windmills are very useful as they produce electricity.

→ Air helps in the dispersal of seeds, pollens, and movement of sailing boats, yachts, gliders, aeroplanes, etc.

→ Dispersal of pollens is known as pollination.

→ Ozone present in the upper layer of the atmosphere protects us from the UV rays of the sun.

→ Air: It is a mixture of many gases like nitrogen, oxygen, carbon dioxide, water vapours, etc.

→ Wind: The moving air is wind.

→ Windmill: A device that is being rotated by air and is used for producing electricity.

→ Atmosphere: The thin blanket of air surrounding the earth constitutes the atmosphere.

PSEB 6th Class Science Notes Chapter 14 Water

April 2, 2024April 1, 2024 by Bhagya

This PSEB 6th Class Science Notes Chapter 14 Water will help you in revision during exams.

PSEB 6th Class Science Notes Chapter 14 Water

→ Water is a vital resource and is considered a boon to live.

→ Water is present all over the earth.

→ Around the 3/4th part of the earth, the surface is covered with water.

→ The human body consists of 70% of water.

→ We need water for our daily activities and for producing other things.

→ Two main sources of water are surface water and groundwater.

→ Water exists in three states i.e. solid, liquid, and gas.

→ We get water from ponds, lakes, rivers, wells, etc.

→ Sea or Ocean water is salty. It is not fit for drinking and for domestic, agricultural, and industrial needs.

→ As water is a vital resource so it must be conserved.

→ Judicious use of water and saving it is conservation of water.

→ Rainwater is a pure form of water and is safe for drinking.

→ Rainwater harvesting is a technique that conserves water by storage of rainwater. This water can be reused for different useful purposes.

→ The water cycle is a cyclic process in which water is circulated between the earth and the atmosphere.

→ Ocean water supplies water to the water cycle and thus plays an important role.

→ Water from oceans, lakes, wet clothes and plants gets evaporated.

→ Clouds are just the condensation of evaporated water in the air.

→ Clouds cause rains and water returns to earth, oceans, lakes, etc.

→ Snow on mountains melts and water runs into rivers.

→ Water is also absorbed by the ground and becomes available to us as groundwater.

→ Heavy rains and no rains cause too many problems.

→ Heavy rains cause floods which destroy lives and properties.

→ Overflow of water in a large amount beyond its normal limits is known as a flood.

→ A flood is a natural disaster.

→ No rain or very little rain in a region is caused by the drought.

→ In drought conditions availability of food, fodder, and water become negligible.

→ With the increase of population, industries, and agriculture also increase which lay stress on the use of water.

→ Melting: The process of conversion of solid into liquid is called melting.

→ Freezing: The process of converting liquid into solid is called freezing.

→ Evaporation: The process of converting liquid into its vapours is called evaporation.

→ Transpiration: The process by which plants lose their water in the air is called transpiration.

→ Condensation: The process of conversion of water vapours into water is called condensation.

→ Precipitation: Falling of water in the form of rain and snow is called precipitation.

→ Clouds: The condensed water droplets join together to form clouds.

→ Water cycle: The evaporation of water to air, formation of clouds by condensation, and falling of rain on the earth constitutes the water cycle in nature.

→ Rainwater harvesting: Collection of rainwater for use at a time when it is not available otherwise is rainwater harvesting.

PSEB 9th Class Maths Solutions Chapter 3 Coordinate Geometry Ex 3.3

April 2, 2024April 1, 2024 by Bhagya

Punjab State Board PSEB 9th Class Maths Book Solutions Chapter 3 Coordinate Geometry Ex 3.3 Textbook Exercise Questions and Answers.

PSEB Solutions for Class 9 Maths Chapter 3 Coordinate Geometry Ex 3.3

Question 1.
In which quadrant or on which axis does each of the points (- 2, 4), (3, – 1), (- 1, 0), (1, 2) and (- 3, – 5) lie? Verify your answer by locating them on the Cartesian plane.
Answer:
PSEB 9th Class Maths Solutions Chapter 3 Coordinate Geometry Ex 3.3 1

Coordinates of the point	Position of the point
(- 2, 4)	In the 2^nd quadrant
(3, – 1)	In the 4^th quadrant
(- 1, 0)	On the x-axis
(1, 2)	In the 1^st quadrant
(- 3, – 5)	In the 3^rd quadrant

Question 2.
Plot the points (x, y) given in the following table on the plane, choosing suitable units of distance on the axes:
PSEB 9th Class Maths Solutions Chapter 3 Coordinate Geometry Ex 3.3 2
Answer:

PSEB 6th Class Science Notes Chapter 13 Fun with Magnets

April 2, 2024April 1, 2024 by Bhagya

This PSEB 6th Class Science Notes Chapter 13 Fun with Magnets will help you in revision during exams.

PSEB 6th Class Science Notes Chapter 13 Fun with Magnets

→ Magnetite is a natural magnet.

→ Some rocks have the property of attracting pieces of iron and these are called natural magnets.

→ Magnet has the property of attracting iron, cobalt, and nickel. Such substances are called magnetic substances.

→ Every magnet has two poles:

North Pole
South pole

→ A freely suspended magnet sets itself in a North-South direction.

→ Unlike (opposite) poles of two magnets attract each other whereas like poles repel each other.

→ Man-made magnets are called artificial magnets.

→ Magnets made from iron pieces are called artificial magnets.

→ Magnets are of different shapes such as Bar magnet, Horseshoe shaped (U-shaped) magnet, cylinderical magnet, or spherical magnet.

→ Compass is used to find direction.

→ When a magnet is brought near a compass, its needle gets deflected.

→ On heating a magnet, striking it with a hammer, or dropping it from a height it loses its property of magnetism.

→ If a magnet is not properly stored then it loses its property with time.

→ To store bar magnets with safety the opposite poles of two magnets are placed facing each other.

→ The magnet should be kept away from cassettes mobiles, TVs, CDs, and computers, etc.

→ Compass: Compass is a device that is needed to determine direction.

→ Magnet: Such substances which have the property of attracting iron are called magnets.

→ Magnetite: Magnetite is a natural magnet that was first discovered by a Shepherd named Magnus.

→ North pole: That end of a freely suspended magnet that points towards the geographical north direction is called its North pole.

→ South pole: That end of a freely suspended magnet that points towards the geographical south direction is called its South pole.