Class 4

Punjab State Board PSEB 4th Class Maths Book Solutions Chapter 5 Measurement Ex 5.8 Textbook Exercise Questions and Answers.

PSEB Solutions for Class 4 Maths Chapter 5 Measurement Ex 5.8

1. In which unit we shall measure the capacity of given things millilitre or litre? Tick (?) the millilitre or litre :

Question 1.

Question 2.

Solution:
Millilitre

Question 3.

Solution:
Litre

Question 4.

Solution:
Millilitre

Question 5.

Solution:
Litre

Question 6.

Solution:
Millilitre

Question 7.

Solution:
Millilitre

Question 8.

Solution:
Litre

Question 9.

Solution:
Litre

Question 10.

Solution:
Litre

Question 11.

Solution:
Millilitre

Question 12.

Solution:
Millilitre

2. Write litre or millilitre according to capacity of given things :

Question 1.

200 ………………
Solution:
Millilitre

Question 2.

50 …………….
Solution:
Millilitre

Question 3.

20 ………………
Solution:
Millilitre

Question 4.

5 ……………..
Solution:
Litre

Question 5.

1 …………….
Solution:
Litre

Question 6.

25 …………….
Solution:
Litre

3. Find out the quantity of liquid in both containers and also find the sum and write in millitres:

Question 1.

700 ml + 500 ml = 1200 ml

Question 2.

…………….. ml + ……………. ml = …………….. ml
Solution:
900 ml + 200 ml = 1100 ml

Question 3.

…………….. ml + ……………. ml = …………….. ml
Solution:
400 ml + 1000 ml = 1400 ml

Question 4.

…………….. ml + ……………. ml = …………….. ml
Solution:
550 ml + 750 ml = 1300 ml

Question 5.

…………….. ml + ……………. ml = …………….. ml
Solution:
650 ml + 850 ml = 1500 ml

Question 6.

…………….. ml + ……………. ml = …………….. ml
Solution:
300 ml + 950 ml = 1250 ml

4. Coloured the glasses according to given capacity:

Question 1.

600 ml
Solution:

Question 2.

200 ml
Solution:

Question 3.

500 ml
Solution:

Question 4.

800 ml
Solution:

Question 5.

450
Solution:

Question 6.

1 litre
Solution:

Question 5.
Take some items. Estimate their capacity and measure their actual capacity with measuring cylinder . Complete the table.

Solution:
Try yourself.

Question 6.
In given containers one is shaded. Shade the another container in such a way that capacity of both the containers become one litre :

Solution:

Punjab State Board PSEB 4th Class Maths Book Solutions Chapter 5 Measurement Ex 5.7 Textbook Exercise Questions and Answers.

PSEB Solutions for Class 4 Maths Chapter 5 Measurement Ex 5.7

Question 1.
Add :
(a) 8 kg 450 gm + 1 kg 210 gm
Solution:

(b) 5 kg 675 gm + 2 kg 205 gm
Solution:

(c) 3 kg 225 gm + 7 kg 527 gm
Solution:

(d) 3 kg 050 gm + 1 kg 400 gm
Solution:

(e) 9 kg 100 gm + 5 kg 075 gm
Solution:

(f) 4 kg 650 gm + 6 kg 275 gm
Solution:

Question 2.
Subtract:

(a) 5 kg 845 gm — 2 kg 525 gm
Solution:

(b) 9 kg 605 gm — 6 kg 275 gm
Solution:

(c) 8 kg 360 gm — 3 kg 150 gm
Solution:

(d) 6 kg 320 gm— 4 kg 175 gm
Solution:

(e) 4 kg 500 gm — 1 kg 250 gin
Solution:

(f) 7 kg 425 gm — 6 kg 280 gm
Solution:

Question 3.
Dilpreet bought 5 kg 500 gm of potatoes and 2 kg 250 gm cauliflower. How much vegetables did he buy ?
Solution:
Dilpreet bought quantity of potatoes = 5 kg 500 gm
Dilpreet bought quantity of cauliflower = 2 kg 250 gm
Total quantity of vegetables bought = 7 kg 750 gm

Question 4.
Harjot’s weight is 20 kg 500 gm less than that of his brother. If his brother’s weight is 62 kg 750 gm. Find the weight of Harjot.
Solution:
Weight of Harjot’s Brother = 62 kg 750 gm
Harjot’s weight is less than his brother’s weight by = -20 kg 500 gm
Weight of Haijot = 42 kg 250 gm

Question 5.
A dealer bought 80 kg 500 gm apples. He sold 4 kg 400 gm. What is the weight of remaining apples ?
Solution:
Quantity of apples bought = 80 kg 500 gm
Quantity of apples sold = 4 kg 400 gm
Weight of remaining apples = 76 kg 100 gm

Question 6.
An NGO distributed roasted gram (Chana) packets in flood affected area. The weight of every packet is 2 kg. NGO distributed 450 packets. How many kgs of packets they distributed ?
Solution:
Weight of each packet = 2 kg
Total number of packets distributed = 450
Total weight of packets distributed = 2 kg × 450
= 900 kg.

Punjab State Board PSEB 4th Class Maths Book Solutions Chapter 5 Measurement Ex 5.9 Textbook Exercise Questions and Answers.

PSEB Solutions for Class 4 Maths Chapter 5 Measurement Ex 5.9

1. Add the following :

Question 1.
8 litre 675 ml + 1 litre 210 ml
Solution:

Question 2.
3 litre 225 ml + 2 litre 205 ml
Solution:

Question 3.
2 litre 605 ml + 7 litre 327 ml
Solution:

Question 4.
4 litre 175 ml + 2 litre 290 ml
Solution:

Question 5.
9 litre 220 ml + 2 litre 735 ml
Solution:

Question 6.
5 litre 125 ml + 8 litre 425 ml
Solution:

2. Subtract :

Question 1.
5 litre 470 ml – 3 litre 315 ml
Solution:

Question 2.
6 litre 705 ml – 5 litre 550 ml
Solution:

Question 3.
4 litre 970 ml – 1 litre 237 ml
Solution:

Question 4.
6 litre 500 ml – 2 litre 370 ml
Solution:

Question 5.
7 litre 075 ml – 2 litre 025 ml
Solution:

Question 6.
9 litre 700 ml – 7 litre 425 ml
Solution:

Question 3.
A confectioner required 75 litre of milk for making condensed milk (khoya), 40 litre of milk for cheese and 8 litre of milk for tea. How many litres of milk does he require ?
Solution:
Milk required by the confectioner for making condensed milk = 75 litre
Milk required by the confectioner for making cheese = 40 litre
Milk required by the confectioner for making tea = 8 litre
Total quantity of milk required by him = 123 litre

Question 4.
Sunita’s mom bought 5 litre 500 ml milk. She used 2 litre milk for Rice pudding (kheer). How much milk was left ?
Solution:
Quantity of milk bought by Sunita’s mom = 5 l 500 ml
Quantity of milk used for rice pudding (Kheer) = 2 l 1000 ml
Quantity of milk left = 3 l 500 ml

Question 5.
The capacity of a water tank is 750 litre. There is 475 litre water in it. How much more water is required to fill the tank?
Solution:
The capacity of water tank = 750 litre
Quantity of water already in it = 475 litre
Quantity of more water required = 275 litre

Punjab State Board PSEB 4th Class Maths Book Solutions Chapter 5 Measurement MCQ Questions and Answers.

PSEB 4th Class Maths Chapter 5 Measurement MCQ Questions

Tick (✓) on the right answer :

Question 1.
What is the standard unit of length ?
(a) litre
(b) metre
(c) gm
(d) kilogram
Answer:
(b) metre

Question 2.
What is the standard unit to measure weight ?
(a) gm
(b) centimetre
(c) metre
(d) litre.
Answer:
(a) gm

Question 3.
35 metre = ………. cm
(a) 350 centimetre
(b) 3500 cm
(c) 35000 cm
(d) none of these.
Answer:
(b) 3500 cm

Question 4.
40 mm = ……….. cm
(a) 400 cm
(b) 4000 cm
(c) 4 cm
(d) none of these.
Answer:
(c) 4 cm

Question 5.
1 kilogram = …………….. gram.
(a) 10 gm
(b) 1000 gm
(c) 100 gm
(d) none of these.
Answer:
(b) 1000 gm

Question 6.
6000 gm = ………….. kg.
(a) 5
(b) 8
(c) 7
(d) 6
Answer:
(d) 6

Question 7.
22 litre = ………….. ml.
(a) 220 ml
(b) 22000 ml
(c) 2200 ml
(d) none of these.
Answer:
(b) 22000 ml

Question 8.
Capacity of 1 glass is 250 ml. How many such glasses will be filled from the bottle of 2 litres ?
(a) 10
(b) 6
(c) 4
(d) 8
Answer:
(d) 8

Question 9.
Manjot’s father bought 40 kg onion and 50 kg potatoes from the market. How much vegetables did he buy ?
(a) 70 kg
(b) 90 kg
(c) 80 kg
(d) 100 kg.
Answer:
(b) 90 kg

Question 10.
A water tank contains 800 litre water. If 350 litre is used. How many litres of water is left in the water tank ?
(a) 300 litre
(b) 400 litre
(c) 450 litre
(d) 200 litre
Answer:
(c) 450 litre

Punjab State Board PSEB 4th Class Maths Book Solutions Chapter 5 Measurement Ex 5.6 Textbook Exercise Questions and Answers.

PSEB Solutions for Class 4 Maths Chapter 5 Measurement Ex 5.6

Question 1.
Raju’s mother bought following things from the market. Find out which items she bought in kg and which items in grams :
(a)

potatoes 3……..
Solution:
kg

(b)

Cauliflower 800 ………
Solution:
gm

(c)

tomato 500 ……..
Solution:
gm

(d)

onion 2……………
Solution:
kg

(e)

chilly 200…………
Solution:
gm

(f)

turmeric 250 ………..
Solution:
gm

(g)

sugar 5 ………….
Solution:
kg

(h)

salt 1 …………
Solution:
kg

(i)

daal 1 ………..
Solution:
kg

(j)

rice 2 …………
Solution:
kg

(k)

grapes 700 ………..
Solution:
gm

(l)

peas 500…………
Solution:
gm

(m)

jaggery (Gurhh) 3 ………..
Solution:
kg

(n)

tea 500 ………..
Solution:
gm

(o)

gold bangle 15 ……….
Solution:
gm

(p)

wheat 25 …………
Solution:
kg

Question 2.
Find the weight :
(a) Weight of carrots is 1 kg and 500 gm.

Solution:
1 kg 500 gm

(b) Weight of ladoos is …… kg …… gm

Solution:
1 kg 200 gm

(c) Weight of brinjal is …… kg ……. gm

Solution:
2 kg 100 gm

(d) Weight of pumpkin is …… kg …… gm.
Solution:
2 kg 300 gm

Question 3.
Take some items. Estimate the weight of such items and also measure the actual weight by using standard weights and weighing balance and fill up in the table :

Solution:
Try yourself.

Question 4.
Complete the table :

Solution:
(a) 1 kg 700 gm, 1700 gm
(b) 1 kg 900 gm, 1900 gm,
(c) 2 kg 500 gm, 2500 gm
(d) 3 kg 350 gm, 3350 gm
(e) 1 kg 700 gm, 1700 gm
(f) 1 kg 350 gm, 1350 gm.

Question 5.
To measure 1 kg, how many standard weighing units are missing in the following and draw them :

Solution:

Punjab State Board PSEB 4th Class Maths Book Solutions Chapter 4 Money (Currency) MCQ Questions and Answers.

PSEB 4th Class Maths Chapter 4 Money (Currency) MCQ Questions

Multiple Choice Questions (MCQ)

Question 1.
How many 50 paise coins are there in ₹ 10 ?
(a) ₹ 4
(b) ₹ 6
(c) ₹ 20
(d) ₹ 13
Answer:
(c) ₹ 20

Question 2.
28 coins of 50 paise will make ₹.
(a) ₹ 50
(b) ₹ 10
(c) ₹ 28
(d) ₹ 14.
Answer:
(d) ₹ 14

Question 3.
Shikha bought, items worth ₹ 65. She gave ₹ 100 note to shopkeeper. How many rupees will she get back from shopkeeper ?
(a) ₹ 25
(b) ₹ 35
(c) ₹ 45
(d) ₹ 50.
Answer:
(b) ₹ 35

Question 4.
Sudhir bought a chocolate worth ₹ 40 and a pastry worth ₹ 35. How much did he spend ?
(a) ₹ 55
(b) ₹ 5
(c) ₹ 75
(d) ₹ 80
Answer:
(c) ₹ 75

Question 5.
Arun bought a pencil worth ₹ 5, eraser worth ₹ 2 and a pen worth ₹ 10. He gave ₹ 20 rupee note to shopkeeper. How many rupees will he get back ?
(a) ₹ 3
(b) ₹ 17
(c) ₹ 22
(d) ₹ 15
Answer:
(a) ₹ 3

Punjab State Board PSEB 4th Class Maths Book Solutions Chapter 5 Measurement Ex 5.5 Textbook Exercise Questions and Answers.

PSEB Solutions for Class 4 Maths Chapter 5 Measurement Ex 5.5

Question 1.
Add the following :
(a) 8 m 40 cm + 4 m 35 cm
Solution:

(b) 2 m 62 cm + 6 m 25 cm
Solution:

(c) 5 m 37 cm + 7 m 20 cm
Solution:

(d) 3 m 45 cm + 6 m 15 cm
Solution:

(e) 1 m 50 cm + 2 m 25 cm
Solution:

(f) 9 m 44 cm + 5 m 35 cm
Solution:

Question 2.
Subtract :
(a) 9 m 70 cm – 7 m 35 cm
Solution:

(b) 6 m 84 cm – 1 m 35 cm
Solution:

(c) 5 m 72 cm – 3 m 60 cm
Solution:

(d) 4 m 18 cm – 3 m 12 cm
Solution:

(e) 9 m 50 cm – 4 m 25 cm
Solution:

(f) 5 m 81 cm – 5 m 75 cm
Solution:

Question 3.
Maya uses lm 50cm red ribbon and 2m25cm green ribbon to make a flower. How much total ribbon did she use ?
Solution:
Length of red ribbon used = 1 m 50 cm
Length of green ribbon used = 2 m 25 cm
Total Length of used = 3 m 75 cm

Question 4.
Saroj bought 5m50cm cloth for herself and 3m25cm for her daughter. Find the total length of cloth did she buy ?
Solution:
Saroj bought cloth for herself = 5 m 50 cm
Saroj bought cloth for her daughter = + 3 m 25 cm
Total length of cloth she bought = 8 m 75 cm

Punjab State Board PSEB 4th Class Maths Book Solutions Chapter 4 Money (Currency) Ex 4.5 Textbook Exercise Questions and Answers.

PSEB Solutions for Class 4 Maths Chapter 4 Money (Currency) Ex 4.5

1. Divide the following amounts :

Question 1.
₹ 160 ÷ 4
Solution:

∴ ₹ 160 ÷ 4 = ₹ 40

Question 2.
₹ 475 ÷ 5
Solution:

∴ ₹ 475 ÷ 5 = ₹ 95

Question 3.
₹ 564 ÷ 12
Solution:

∴ ₹ 564 ÷ 12 = ₹ 47

Question 4.
₹ 1248 ÷ 6
Solution:

∴ ₹ 1248 ÷ 6 = ₹ 208

Question 5.
₹ 2665 ÷ 13
Solution:

∴ ₹ 2665 ÷ 13 = ₹ 205

Question 2.
The cost of 18 toy cars is ₹ 450. Find the cost of one toy car ?
Solution:
Cost of 18 toy cars = ₹ 450
Cost of 1 toy car = ₹ 450 ÷ 18
= ₹ 25

Question 3.
The cost of 13 books is ₹ 936. Find the cost of one book.
Solution:
Cost of 13 books = ₹ 936
Cost of 1 book = ₹ 936 ÷ 13
= ₹ 72.

Question 4.
The cost of a dozen oranges is ₹ 84. Find the cost of one orange.
Solution:
Cost of one dozen i.e. 12 oranges = ₹ 84
Cost of one orange = ₹ 84 ÷ 12
= ₹ 7

Question 5.
An amount of ₹ 2848 is to be distributed among 16 children. What amount will each child get ?
Solution:
Amount to be distributed among 16 children = ₹ 2848
Amount received by each child = ₹ 2848 ÷ 16
= ₹ 178

Question 6.
A school received ₹ 9120 to buy uniforms for 19 children of class 4. How much amount did the school get for each uniform.
Solution:
Total amount received by the school = ₹ 9120
No. of children = 19
Amount of money school received for each uniform
= ₹ 9120 ÷ ₹ 19
= ₹ 480.

Punjab State Board PSEB 4th Class Maths Book Solutions Chapter 5 Measurement Ex 5.4 Textbook Exercise Questions and Answers.

PSEB Solutions for Class 4 Maths Chapter 5 Measurement Ex 5.4

Question 1.
Draw a line segment by joining the given points and measure their lengths:

Solution:
(a)

(b)

(c)

Question 2.
Draw line segment of given lengths:
(a) 5 cm
Solution:

(b) 8 cm
Solution:

(c) 6 cm
Solution:

(d) 2 cm
Solution:

(e) 7 cm
Solution:

(f) 9 cm
Solution:

Punjab State Board PSEB 4th Class Maths Book Solutions Chapter 4 Money (Currency) Ex 4.4 Textbook Exercise Questions and Answers.

PSEB Solutions for Class 4 Maths Chapter 4 Money (Currency) Ex 4.4

1. Find the product:

Question 1.
₹ 25 × 6
Solution:

Question 2.
₹ 30 × 7
Solution:

Question 3.
₹49 × 8
Solution:

Question 4.
₹ 175 × 8
Solution:

Question 5.
₹ 400 × 5
Solution:

Question 6.
₹ 312 × 3
Solution:

Question 7.
₹ 27 × 15
Solution:

Question 8.
₹ 48 × 76
Solution:

Question 9.
₹ 82 × 67
Solution:

Question 2.
The cost of a doll is ₹ 70. Find the cost of 5 such dolls.
Solution:
Cost of.4oll = ₹ 70
Cost of 5 dolls = ₹ 70 × 5
= ₹ 350

Question 3.
Manveet bought a jacket of ₹ 460. Find the cost of 9 such jackets.
Solution:
Cost of jacket = ₹ 460
Cost of 9 jackets = ₹ 460 × 9 = ₹ 4,140

Question 4.
Sukhdev bought 35 balloons ₹ 15 per balloon. How much did he pay to the balloon seller ?
Solution:
Cost of 1 balloon = ₹ 15
Cost of 35 balloons = ₹ 15 × 35 = ₹ 525

Question 5.
The cost of a banana is ₹ 8. What is the cost a dozen bananas ?
Solution:
Cost of 1 banana = ₹ 8
Cost of 1 dozen i.e. 12 bananas = ₹ 8 × 12
= ₹ 96.